72 lines
2.0 KiB
Python
72 lines
2.0 KiB
Python
import itertools
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length = 5
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digits = set(range(10))
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numbers = set(itertools.product(digits, repeat=length))
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print(f"|Z| = {len(digits)}")
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print(f"|N| = {len(numbers)}")
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counter = 0
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for n in numbers:
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if len(set(n)) == 1:
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counter += 1
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print(f"|A| = {counter}")
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# Ausgabe: |A| = 10
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counter = 0
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for n in numbers:
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if sum(n.count(x) == 4 for x in set(n)) > 0:
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counter += 1
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print(f"|B| = {counter}")
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# Ausgabe: |B| = 450
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counter = 0
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for n in numbers:
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if len(set(n)) == 3 and any(n.count(x) == 3 for x in set(n)):
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counter += 1
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print(f"|C| = {counter}")
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# Ausgabe: |C| = 7200
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counter = 0
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for n in numbers:
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if len(set(n)) == 2 and any(n.count(x) == 3 for x in set(n)):
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counter += 1
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print(f"|D| = {counter}")
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# Ausgabe: |D| = 900
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counter = 0
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for n in numbers:
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if len(set(n)) == 3 and any(x != y and n.count(y) == 2 and n.count(x) == 2 for x in set(n) for y in set(n)):
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counter += 1
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print(f"|E| = {counter}")
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# Ausgabe: |E| = 10800
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counter = 0
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for n in numbers:
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if len(set(n)) == 5:
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counter += 1
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print(f"|F| = {counter}")
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# Ausgabe: |F| = 30240
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def contains_twin_pair(combo):
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"""Check if the combination contains at least one twin pair."""
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for x in range(len(combo)):
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for y in range(len(combo)):
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if abs(combo[x] % 49 - combo[y] % 49) == 1:
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return True
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return False
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# Generate all combinations of 6 numbers out of 49
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numbers = list(range(1, 50))
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all_combinations = list(itertools.combinations(numbers, 6))
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# Filter combinations with and without twin pairs
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combinations_with_twin = [combo for combo in all_combinations if contains_twin_pair(combo)]
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combinations_without_twin = [combo for combo in all_combinations if not contains_twin_pair(combo)]
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# Output the count of combinations
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print(len(all_combinations))
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print(f"Number of combinations with at least one twin pair: {len(combinations_with_twin)}")
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print(f"Number of combinations without any twin pairs: {len(combinations_without_twin)}")
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print(len(combinations_with_twin)/len(all_combinations)) |